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Dacă y+radical5-{2,8(3)}-[radical5-8]={5/3}+{7,0(6)}+3+radical5},sa se determine{Y},[Y],[6y].


Răspuns :

102533

Răspuns:

Explicație pas cu pas:

y + √5 - {2,8(3)} - [√5-8] = {5/3} + {7,0(6)+3+√5}

{5/3} + {7,0(6)+3+√5} = 0,(6) + {10,0(6) + 2,236} =

= 0,(6) + {12,302(6)} = 0,(6) + 0,302(6) = 1,002(5)

y + √5 - {2,8(3)} - [√5-8] ≈ y + 2,236 - 0,8(3) + 0,236 =

= y + 2 - 0,8(3) = y + 2 - (83-8)/90 = y + 2 - 5/6 = y + 7/6 =

= y + 1,1(6)

=> y + 1,1(6) = 1,002(5)  =>

y = 1,002(5) - 1,1(6) = (10025-1002)/9000 - (116-11)/90 =

= 9023/9000 - 10500/9000 = -1477/9000 => y = -0,164(1)

{y} = 0,835(8)  ; [y] = -1  ; [6y] = [-0,984(6)] = -1