ABC con circular drept
BC=8 cm
AB,AC=10 cm
{O}= Perpendiculara tarasa din A in mijl lat BC
a) triunghiul AOB ; m(O)=90 grade=>T.P => AO²=AB²-BO²(BO este egal cu jum din R)
AO²=10²-4²
AO²=100-16
AO=√84
AO=2√21 (AO =h)
b)At=Al+Ab
At=πRG+πR²
At=π8×10+π8²
At=80π+64π
At=144π cm²
c)V=πR²×h/3
V=π64×2√21/3
V=128√21/3 cm³
