[tex]\it \ell)\ \sqrt{\dfrac{12}{125}}=\sqrt{\dfrac{4\cdot3}{25\cdot5}}=\dfrac{2}{5}\sqrt{\dfrac{3}{5}}\\ \\ \\ k)\ \sqrt{\dfrac{8}{27}}=\sqrt{\dfrac{4\cdot2}{9\cdot3}}=\dfrac{2}{3}\sqrt{\dfrac{2}{3}}\\ \\ \\ j)\ \sqrt{\dfrac{72}{169}}=\dfrac{\sqrt{36\cdot2}}{13}=\dfrac{6\sqrt2}{13}\\ \\ \\ i)\ \sqrt{\dfrac{45}{32}}=\sqrt{\dfrac{9\cdot5}{16\cdot2}}=\dfrac{3}{4}\sqrt{\dfrac{5}{2}}[/tex]
[tex]\it h)\ \sqrt{\dfrac{8}{3}}=\sqrt{\dfrac{4\cdot2}{3}}=2\sqrt{\dfrac{2}{3}}\\ \\ \\ g)\ \sqrt{\dfrac{3^5}{54}}=\sqrt{\dfrac{3^5}{27\cdot2}}=\sqrt{\dfrac{3^5}{3^3\cdot2}}=\sqrt{\dfrac{3^2}{2}}=\dfrac{^{\sqrt2)}3}{\ \ \sqrt2}=\dfrac{3\sqrt2}{2}[/tex]
