Răspuns:
a)
[tex]= \sqrt{(2^{3})^{2} *2} =\sqrt{(2^{3})^{2}}*\sqrt{2} =2^{3} \sqrt{2} =8\sqrt{2}[/tex]
b)
[tex]= \sqrt{(3^{5})^{2} *3} =\sqrt{(3^{5})^{2}}*\sqrt{3} =3^{5} \sqrt{3} =243\sqrt{3}[/tex]
c)
[tex]= \sqrt{(2^{2})^{2} *2*(3^{3})^{2} *3} =\sqrt{(2^{2})^{2}}*\sqrt{2*3} *\sqrt{(3^{3})^{2}}=[/tex]
[tex]=2^{2}*3^{3} \sqrt{6} =4*27\sqrt{6}=108\sqrt{6}[/tex]
d)
[tex]= \sqrt{3^{2} *3*(5^{2})^{2} *5*(7^{3})^{2} *7} =\sqrt{3^{2}} *\sqrt{(5^{2})^{2}}*\sqrt{(7^{3})^{2}}*\sqrt{3*5*7}=[/tex]
[tex]=3 *5^{2}*7^{3}*\sqrt{105}=3 *25*343*\sqrt{105}=25725\sqrt{105}[/tex]
e) si f) nu apar complete pe fotografie
g)
[tex]=\sqrt{2^{2n} *2} =\sqrt{(2^{n})^{2} *2} =\sqrt{(2^{n})^{2} }*\sqrt{2} =2^{n}\sqrt{2}[/tex]
h)
[tex]=\sqrt{3^{2n+2} *3} =\sqrt{(3^{n+1})^{2} *3} =\sqrt{(3^{n+1})^{2} }*\sqrt{3} =3^{n+1}\sqrt{3}[/tex]
Explicație pas cu pas:
