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Claudyapysy
a fost răspuns

[tex] a)x^{2} -4x=0
b)2 x^{2} +x=0
c)-4 x^{2} +6x=0
d)5 x^{2} =0[/tex]

Răspuns :

Cristinatibulca
a)  [tex] x^{2} -4x=0 x(x-4)=0[/tex]⇒x=0, x=4

b) 2x²+x=0
x(2+x)=0, x=0, x=-2

c)  -4x²+6x=0
-2x(2x-3)=0
x=0, x=2/3
d) 5x²=0, x=0

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