[tex] \frac{96}{10}-3 \frac{9}{9}+ \frac{25}{100}- \frac{21}{10}[/tex]
simplificam ce se poate
=[tex] \frac{48}{5}-3+ \frac{1}{4}- \frac{21}{10}[/tex]
aducem la acelasi numitor, adica 20
=[tex] \frac{192}{200}- \frac{60}{20}+ \frac{5}{20}- \frac{42}{20}[/tex]
=[tex] \frac{95}{20} [/tex]
=[tex] \frac{19}{4} [/tex]
