Amestec echimolecular => x:x
1mol..........232g
H-CH=O + Ag2O -> HCOOH + 2Ag
xmoli.........232x
1mol...............232g
CH3-COOH + Ag2O -> CH3-COOH + 2Ag
xmoli..............232x
464x=69,6 => x=0,15 moli
mmetanal=0,15*Mmetanal=0,15*30=4,5g metanal
m etanal=0,15*M etanal=0,15*44=6,6g etanal
mamestec=4,5+6,6=11,1g amestec