Explicație:
1 mol......6,022*10^23 molecule CO2
x mol....12,046*10^23 molecule CO2
[tex]x = \frac{12.046 \times 10 {}^{23} }{6.022 \times 10 {}^{23} } [/tex]
x=2 moli aproximativ
[tex]n = \frac{m}{m} [/tex]
M CO2=12+16×2= 12+32= 44 g/mol
[tex]2 = \frac{m}{44} [/tex]
m=44×2=88g CO2
