Răspuns :
Răspuns:
[3;4)
[1;1,5)
[3;11/3)
Explicație pas cu pas:
*
x∈[3;4)
**
2x∈[2;3)
x∈[1;1,5)
***
5≤(3x+1)/2<6
10≤3x+1<12
9≤3x<11
x∈[3,11/3)
[tex]\it [x]=3 \Rightarrow x\in [3,\ \ 4)\\ \\ \ [\it2x]=2 \Rightarrow 2x\in[2,\ 3)|_{:2} \Rightarrow x\in[1;\ 1,5)[/tex]
[tex]\it\Big[ \dfrac{3x+1}{2}\Big] =5 \Rightarrow 5\leq\dfrac{3x+1}{2}<6|_{\cdot2} \Rightarrow 10\leq3x+1<12|_{-1} \Rightarrow \\ \\ \\ \Rightarrow 9\leq3x<11|_{:3} \Rightarrow3\leq x<\dfrac{11}{3} \Rightarrow x\in\Big[3,\ \dfrac{11}{3}\Big)[/tex]