Răspuns:
b)
[tex]= 3 +\frac{22+2}{11} (\frac{125}{100}-\frac{3}{9} )= 3+\frac{24}{11} (\frac{5}{4} -\frac{1}{3} )=[/tex]
[tex]= 3+\frac{24}{11} *\frac{5*3-4}{12}=3+\frac{2}{11} *(15-4)=3+2 = 5[/tex]
c)
[tex]=(\frac{3+1}{3} +\frac{16-1}{90} )^{2} :\frac{15}{10} -\frac{1}{2} =(\frac{4}{3} +\frac{15}{90} )^{2} *\frac{2}{3} -\frac{1}{2}=[/tex]
[tex]=(\frac{4}{3} +\frac{1}{6} )^{2} *\frac{2}{3} -\frac{1}{2}=(\frac{8+1}{6} )^{2} *\frac{2}{3} -\frac{1}{2}=[/tex]
[tex]=\frac{3}{2} * \frac{3}{2} *\frac{2}{3} -\frac{1}{2}=\frac{3}{2} -\frac{1}{2}=\frac{2}{2} =1[/tex]
Explicație pas cu pas:
