Răspuns:
[tex]\bf \dfrac{5x-1}{10}=\dfrac{2x-3}{6}+\dfrac{^{2)} 1~}{3}[/tex]
[tex]\bf \dfrac{5x-1}{10}=\dfrac{2x-3+2}{6}\implies \dfrac{5x-1}{10}=\dfrac{2x-1}{6}\implies[/tex]
[tex]\bf 6\cdot(5x-1)=10\cdot(2x-1)\implies 30x-6=20x-10\implies[/tex]
[tex]\bf 30x-20x=-10+6\implies 10x =-4\implies[/tex]
[tex]\red{\boxed{\bf x =-\frac{2}{5} }}[/tex]
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