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Danailagabriela
a fost răspuns

Ajutatima va rog imi trebuie pe azi. 7(x-3)=49 ;;;;; 5(x+2)=32 ;;;; 3(1-2x)+8=32 ; 1-3(8x-4)=1; 1605+4(3x-x)=2011; 3(x-5)+17=4-4(3x-2); 8(3x-1)-20=5x-2(4x+3). Dau 10 puncte pentru fiecare exercitiu in total 70 puncte

Răspuns :

7(x-3)=49<=>x-3=49÷7<=> x-3=7=>x=10; 5(x+2)=32<=>x+2=32÷5<=>x+2=6,4=>x=4,4; 3(1-2x)+8=32<=>1-2x=(32-8)÷3<=>1-2x=8 =>×=-3,5; 1605+4(3x-x)=2011<=>8x=2011-1605=>x=406÷8=50,75; 3(x-5)+17=4-4(3x- 2)<=>3x-15+17=4-12x+8<=>3x+12x=12-2=>x=10÷15=0,(6); 8(3x-1)-20=5x-2(4x+3)<=>24x-8-20=5x-8x-6<=>24x+3x=28-6=>x=22÷27=0,(814)

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