Răspuns:
(2x-y)²=(2x)²-2*2xy+y²=
4x²-4xy+y²
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(4+2x)²=16+16x+4x²
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(2√2-3a)(2√2+3a)=(2√2)²-9a²=8-9a²
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(3x-2y+√5)²=(3x)²+(-2y)²+√5²+2*3x*(-2y)+2(-2Y)*√5+2√5*3x=
9x²+4y²+5-12xy-4√5y+6√5y
Explicație pas cu pas: