[tex]\bf\frac{8}{x+1}\in N \rightarrow x + 1 \in D_8[/tex]
[tex]\bf x + 1 \in \{1, 2, 4,8\}[/tex]
[tex]\bf x + 1 = 1 \rightarrow x = 1-1 \rightarrow x = 0; 0 \in N\\\bf x + 1 = 2 \rightarrow x = 2-1\rightarrow x = 1; 1 \in N\\\bf x + 1 = 4 \rightarrow x = 4-1 \rightarrow x = 3; 3 \in N\\\bf x + 1 = 8 \rightarrow x = 8-1 \rightarrow x=7; 7\in N[/tex]