[tex]\it Folosim\ \ formula:\ \ \sqrt{a^2}=|a|\\ \\ a)\ \sqrt{(2x-8)^2}=12 \Rightarrow |2x-8|=12 \Rightarrow 2x-8\in\{-12,\ 12\}|_{+8} \Rightarrow \\ \\ \Rightarrow 2x\in\{-4,\ 20\}|_{:2} \Rightarrow x\in\{-2,\ 10\}\\ \\ Ecua\c{\it t}ia\ are\ dou\breve a\ solu\c{\it t}ii:\ x_1=-2,\ \ x_2=10[/tex]
b)
[tex]\it \sqrt{(5x-2)^2}=8 \Rightarrow |5x-2|=8 \Rightarrow 5x-2\in\{-8,\ 8\}|_{+2} \Rightarrow \\ \\ \Rightarrow 5x\in\{-6,\ 10\}|_{:5} \Rightarrow x\in\{-1,2;\ 2\}\\ \\ Ecua\c{\it t}ia\ \ are\ \ dou\breve a\ \ solu\c{\it t}ii:\ \ x_1=-1,2;\ \ \ x_2=2[/tex]
