Răspuns:
Formula compusului este CxHyCl₂
1 mol CxHyCl2 = (12x + y + 71) g
(12x + y + 71) g subst………………71 g Cl
100 g subst………………………….44,09 g Cl
44,09×(12x + y + 71) = 7100
529,08x + 44,09y + 3130,39 = 7100
529,08x + 44,09y = 3969,61
12x/y = 14/1
12x = 14y
x = 14y/12 = 7y/6
529,08×7y/6 + 44,09y = 3969,61
529,08×7y/6 + 44,09y = 3969,61
3703,56y + 264,54y = 23817,66
3968,1y = 23817,66
y= 23817,66 / 3968,1
y = 6
12x = 14×6
12x=84
x=84 / 12
x = 7
C₇H₆Cl₂
Izomeri: 10
D) 10
Explicație:
