[tex]\it \sqrt{1024}=32;\ \ \sqrt{1225}=35;\ \ \sqrt{2025}=45\\ \\ Ecua\c{\it t}ia\ devine:\\ \\ \\ \dfrac{\sqrt{32+32}}{\sqrt{135-35}}=\dfrac{2x}{\sqrt{270-45}} \Rightarrow \dfrac{\sqrt{64}}{\sqrt{100}}=\dfrac{2x}{\sqrt{225}} \Rightarrow \dfrac{8}{10}=\dfrac{2x}{15} \Rightarrow\\ \\ \\ \Rightarrow 20x=120|_{:20} \Rightarrow x=6[/tex]
