Răspuns:
a. Mg + 2CH₃COOH → (CH₃COO)₂Mg + H₂↑
b. 0,5kmol Mg
Explicație:
b.
[tex]\rm n_{Mg}=?[/tex]
[tex]\rm m_{(CH_3COOH)_2Mg}=56,8kg\:(m_p)[/tex]
[tex]\rm\eta=80\%[/tex]
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1. Calculăm masa de magneziu reacționată practic.
x 56,8kg
Mg + 2CH₃COOH → (CH₃COO)₂Mg + H₂↑
24kg 142kg
[tex]\rm M_{(CH_3COOH)_2Mg}=59\times2+24=142\dfrac{kg}{kmol}[/tex]
x = 24 × 56,8kg / 142 = 9,6kg Mg (practic)
2. Calculăm masa de magneziu reacționată teoretic.
[tex]\rm\eta=\dfrac{m_p}{m_t}\times100\implies m_t=\dfrac{m_p}{\eta}\times100[/tex]
[tex]\rm m_{t_{Mg}}=\dfrac{9,6kg}{80}\times100=\bf12kg[/tex]
3. Calculăm numărul de kilomoli de magneziu.
[tex]\rm n=\dfrac{m}{A}[/tex]
[tex]\rm n_{Mg}=\dfrac{12\sout{kg}}{24\dfrac{\sout{kg}}{kmol}}=\bf0,5kmol[/tex]
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