[tex]\it \mathbf{5.}\\ \\ \dfrac{^{2)}3}{\ 5}=\dfrac{6}{10}=0,6\\ \\ \\ \mathbf{6.}\\ \\ \dfrac{^{4)}1}{\ 3}=\dfrac{4}{12}\\ \\ \\ \dfrac{^{6)}1}{\ 2}=\dfrac{6}{12}\\ \\ \\ \dfrac{4}{12}<\dfrac{5}{12}<\dfrac{6}{12}\\ \\ \\ Deci,\ am \ g\breve asit\ num\breve arul\ ra\c{\it t}ional\ \dfrac{5}{12},\ situat\ \^{i}ntre\ \dfrac{1}{3}\ \c{s}i\ \dfrac{1}{2}.[/tex]
