Explicație pas cu pas:
p*|x-1|=|x|
x<0
p(1-x)=-x
p-px=-x
x(p-1)=p
x=p/(p-1)
p/(p-1) <0
=>p€(0,1]
x€(0,1)
p(1-x)=x
p-px=x
x(p+1)=p
x=p/(p+1)
p/(p+1)=<1
p/(p+1)>0
=>p apartine unei multimi vide.
x€(1,+inf)
p(x-1)=x
px-p=x
x(p-1)=p
x=p/(p-1) >1=>p€(1,+inf)
Deci ecuatia are cel putin o solutie pt p€(1,+inf)
Bafta!