Hei! :)
Fie a, b, c, d, e, f, g, h, i, j- 10 numere naturale
[tex]\frac{a + b + c + d + e + f + g + h + i+ j}{10} =23,61\\a + b + c + d + e + f + g + h + i+ j = 23,61*10=236,1\\\\\frac{a+b+c+d}{4}=1,101\\a+b+c+d=1,101*4=4,404\\\\=> (a + b + c + d )+ (e + f + g + h + i+ j) = 236,1\\=> (e + f + g + h + i+ j) = 236,1 - (a + b + c + d ) = 236,1 - 4,404\\=> (e + f + g + h + i+ j) = 231,696\\[/tex]
Asadar, media aritmetica a celorlalte 6 numere este 231,696 :6 = 38,616
