CE x²+3x-10 > 0, delta = 9+40 = 49
x1 = (-3+7)/2 = 4/2 = 2 >0 adevarat
x2 = (-3-7)/2 = -10/2 = -5 >0 fals
deci x apartine (2,infinit)
Folosesti formula loga (b) = c de unde b = a^c
x² +3x-10 =2³
x²+3x-10-8=0
x²+3x-18=0
delta = 9+72 = 81
x1 = (-3+9)/2 = 6/2 = 3 apartine (2,infinit)
x2 = (-3-9)/2 = -12/2 = -6 nu apartine (2,infinit)
Deci S={3}
