Răspuns :
[tex]\it 2\sqrt3=\sqrt{12};\ 2\sqrt6=\sqrt{24};\ 5=\sqrt{25}\\ \\ \sqrt{12}<\sqrt{24}<\sqrt5 \Rightarrow 2\sqrt3<2\sqrt6<5[/tex]
[tex]\it 2\sqrt3=\sqrt{12};\ 2\sqrt6=\sqrt{24};\ 5=\sqrt{25}\\ \\ \sqrt{12}<\sqrt{24}<\sqrt5 \Rightarrow 2\sqrt3<2\sqrt6<5[/tex]