Exercitiul 5 va rog!!!!
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(-x+2)(3x+1)/ (x-3) </ 0
-3x²-x+6x+2 </ 0*(x-3)
-3x(x-2)-(x-2) </ 0
(x-2)(-3x-1) </ 0
-(x-2)(3x+1) </ 0
(x-2)(3x+1) >/ 0
x-2>/ 0 , x>/ 2
3x+1>/ 0 , 3x>/ -1 , x>/ -1/3
deci x apartine [2, infinit)