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Descompunad in factori:a) 16(3x+2)²-9(x+1)² ; b)x⁴-x²+1 ; c) 16x² -40x +25 ; d) (4x-3)² -(2x-1)² ; e) x²+2x-8
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Răspuns :

a)          Este formula   a²-b²=(a-b)(a+b)

16(3x+2)²-9(x+1)²=[4(3x+2)-3(x+1)] ·[4(3x+2)+3(x+1)]=(9x+5)(15x+11)

b)    numai daca = x² ( x²-1 + 1/x²)

c) 16x²-40x+25=(4x-5)²

d) (4x-3)²-(2x-1)²=(4x-3-2x+1)(4x-3+2x-1)=(2x-2)(6x-4)

e) x²+2x-8=0     Δ=4+32=36

x1=(-2-6)/2=-4               x2=(-2+6)/2=2        Pina ce e asa

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