Un calator parcurge in prima zi jumatate din lungimea drumului si inmca 1Km,a doua zi o treime din drum si inca 1 Km,iar in a treia zi ultimii 3 Km.Cati Km are drumul ?Rezolvare pentru cls a v a .
prima zi⇒y/2+1km; a doua zi⇒y/3+1km; a tria zi⇒ultimii 3 km; ⇒y/2+1km+y/3+1km+3km=y ⇒y/2+y/3+[1km+1km+3km]=y ⇒y/2+y/3+5km=y ⇒5km=y-]y/2+y/3] ⇒5km=y-[3y/6+2y/6] ⇒5km=y-5y/6 ⇒5km=6y/6-5y/6 ⇒5km=y/6 ⇒y=6·5km⇒y=30km[are drumul];
