P= AC+BC+AB 4(√3+3)=8+BC+4 4√3+12=12+BC 4√3=BC ARIA Δ ACM= ARIA ΔABM daca M mediana calculam aria Δ ABC CU FORMULA LUI Heron, adica CALCULAM SEMIPERIMETRUL p=(AB+BC+AC)/2=4(√3+3)/2= 2(√3+3) Apoi aplicam formula ariei Aria ABC=√p(p-a)(p-b)(p-c) Aria ABC=√ 2(√3+3)(6-2√3)(2√3+2)(2√3-2)=√2(√3+3)2(3-√3)((2√3)²-2²)=√4(9-3)(4*3-4)=√4*6*(12-4)=√4*6*8=8√3 atunci Aria lui ACM= Aria lui ABC/2= 8√3/2=4√3
