[tex]( \frac{18}{240} - \frac{7}{80} \times \frac{2}{3} + \frac{17}{30} \div \frac{2}{5} ) \div (4 \frac{1}{5} - 3.2 \times 10 - 0.4(5) \times 90) + \frac{1}{48} \\ \\ (\frac{18}{240} - \frac{7}{40} \times \frac{1}{3} + \frac{17}{30} \times \frac{5}{2} ) \div ( \frac{4 \times 5 + 1}{5} - \frac{32}{10} \times 10 - \frac{45 - 4}{90} \times 90) + \frac{1}{48} \\ \\ (\frac{ 18}{240} - \frac{7}{120} + \frac{17}{6} \times \frac{1}{2} ) \div ( \frac{21}{5} - 32 - 41) + \frac{1}{48} \\ \\ (\frac{18}{240} - \frac{14}{240} + \frac{17}{12} ) \div ( \frac{21}{5} - \frac{160}{5} - \frac{205}{5} ) + \frac{1}{48} \\ \\ (\frac{4}{240} + \frac{17 \times 20}{12 \times 20} ) \div ( - \frac{344}{5} ) + \frac{1}{48} \\ \\ ( \frac{4 + 340}{240} ) \times ( - \frac{5}{344} ) \times + \frac{1}{48} \\ \\ \frac{344}{240} \times ( - \frac{5}{344} ) + \frac{1}{48} \\ \\ \frac{1}{48} \times ( - \frac{1}{1} ) + \frac{1}{48} \\ \\ - \frac{1}{48} + \frac{1}{48} = 0[/tex]
pentru că opusul unui numă adunat cu celălalt =0
