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log6 (4x-8)=1 rezolvarea la acest exercitiu​

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[tex]\displaystyle\bf\\log_{_{\b6}}(4x-8)=1\\\\4x-8=6^1\\\\4x-8=6\\\\4x=6+8\\\\4x=14\\\\x=\frac{14}{4}\\\\x=\frac{7}{2}\\\\\boxed{\bf x=3,\!5}[/tex]

 

 

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