Răspuns:
M,CuO=80g/mol
M,H2SO4=98g/mol
M,CuSO4= 160g/mol
80g.............98g............160g...........18g
CuO + H2SO4-----> CuSO4 + H2O
40g.........x........................y.................z
x= 49gH2SO4
y=80gCuSO4
z= 9gH2O
solutia de acid
c=mdx100/ms--> ms= 49x100/40g=122,5 g sol H2SO4
122,5=m,d+ m,apa----> m,apa= 122,5-49=>73,5 g
SOLUTIA FINALA CONTINE DIZOLVATE 80gCuSO4 in apa ramasa de la sol H2SO4 si apa formata in reactie
m,apa= 73,5+9=> 82,5g
md= 80g
c= 80x100/82,5=97%
Explicație:
