Răspuns:
a)Ipoteza:{ΔMNP-dreptunghic in M
MD-inaltime, D∈(NP)
BD=5 cm
m(∠N)=30°}
Concluzie:{m(∠PMD)=?}
Demonstratie:{m(∠MDP)+m(DPM)+m(∠PMD)=180°
90°+m(∠DPM)+m(∠PMD)=180°
m(∠N)+m(∠M)+m(∠P)=180°
90°+30°+m(∠P)=180°
m(∠P)=180°-120°
m(∠P)=60° deci practic m(∠P)=m(∠DPM) deci avem ca
90°+60°+m(∠PMD)=180°
m(∠PMD)=180°-150°
m(∠PMD)=30°
b)Ipoteza:{-idem (la fel ca la punctul a)}
Concluzia:{MP=?}
Demonstratie:{-deoarece am aflat ca la punctul a m(∠PMD)=30°⇒PD= ⇒MP=PD·2
MP=5·2
MP=10 cm
