Răspuns:
AB=AC=>ΔABC isoscel
180°-120°=2∢ABC
60°=2∢ABC=>∢ABB=∢ACB=30°
AC=8√3 }
m(∢ACD)=30° } =>T∢30° DC=AD×2
ΔADC, m(∢ADC)=90° }
AC=8√3 } =>DC²=(DC/2)²+AC²
DC²=DC²/4 +(8√3)²
4DC²/4-DC²/4=192
3DC³/4=192
3DC²=768
DC²=256
DC=√256=>DC=16cm
BD=8cm
N-am idee dacă e corect da e ok=)))