Răspuns:
Explicație:
CuSO4
r.a.=1 : 1 :4
M=64 + 32 +4.16= 160--------> 160g/moli
AgNO3
r.a.= 1 : 1 :3
M= 108 + 14 + 3.16=170-------> 170g/moli
MgS
r.a.= 1 : 1
M=24 +32= 56-------> 56g/moli
NaOH
r.a.= 1: 1: 1
M = 23 + 16 +1=40------->40g/moli
CO
r.a.= 1: 1
M=12 + 16=18-------> 28g/moli
H3PO4
r.a.= 3 : 1 : 4
M= 3 + 31 + 4.16= 98-----------> 98g/moli
HNO2
r.a.= 1 : 1 : 2
M= 1 +14 + 2.16 =47--------> 47g/moli
HCl
r.a.=1 : 1
M= 1 + 35,5=36,5-------> 36,5g/moli
