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Mariusirimia112
a fost răspuns

Alternante: i, a!
(2x3 +5xi) 3x2= 4x 5;
a x 4-15 =(80 - 75) x 5;
(6 x 4-i x 3) +9 x 4 = 3 x 10+ 3 x 3;
96 - (8 x 4 + a x 3) = 5 x 6 + 19;
96 - (9 x 5 - 9 x 1) = 5 x 6 +57;
96 - (5 x 5 + a x 6-40) 2 = 9 x 10.​

Alternante I A2x3 5xi 3x2 4x 5a X 415 80 75 X 56 X 4i X 3 9 X 4 3 X 10 3 X 396 8 X 4 A X 3 5 X 6 1996 9 X 5 9 X 1 5 X 6 5796 5 X 5 A X 640 2 9 X 10 class=

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Crintina72

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(2x3+5xi)-3x2=4x5

(6+5×i)-6=20

(6+5×i)=20+6

6+5×i=26

5×i=26-6

5×i=20

i=20:5

i=4

ax4-15 =(80-75)×5

ax4-15=5×5

a×4-15=25

a×4=25+15

a×4=40

a=40:4

a=10

(6×4-i×3)+9×4=3×10+3×3

(24-i×3)+36=30+9

(24-i×3)+36=39

(24-i×3)=39-36

24-i×3=3

i×3=24-3

i×3=21

x=21:3

x=7

96-(8x4+a×3)=5×6+19

96-(32+a×3)=30+19

96-(32+a×3)=49

32+a×3=96-49

32+a×3=47

a×3=47-32

a×3=15

a=15:3

a=5

96-(9×5-9×i)=5×6+57

96-(45-9×i)=30+57

96-(45-9×i)=87

45-9×i=96-87

45-9×i=9

9xi=45-9

9×i=36

i=36:9

i=4

96-(5×5+a×6-40)×2=9×10

96-(25+a×6-40)×2=90

(25+a×6-40)×2=96-90

(25+a×6-40)×2=6

(25+a×6-40)=6:2

25+a×6-40=3

25+a×6=3+40

25+a×6=43

a×6=43-25

a×6=18

a=18:6

a=3

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