Răspuns:
acolada mare {si faci:x+y+z=0 =>{z+1-6y+z=0
2x- x3=0 2z+2-12y- <=>
4y+4z=-1
x=5y-z=1
{2z-5y=-1 /÷(-3)
6z-16y=-3 =>{-6z+15y=3
6z-16y=-3
________________
/ -y=0=>y=0
2z=-1=>z=-1/2 (1 supra 2); x=-1/2+1-0=>x=1/2
