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Mariusciobi
a fost răspuns

1+2+3+....+2004/2+4+6+....2004=2x-1/x

Răspuns :

Ctinamaria31xxx
1+2+3+....+2004=
2004*2005/2 = 
1002*2005

2+4+6+....2004=
2(1+2+3+......+1002)=
2*1002*1003/2   -2 cu 2 se simplifica
=1002*1003

1002*2005 =
1002*1003

2005/1003=2x-1/x
1003(2x-1)=2005x
2006x-1003=2005x
2006x-2005x=1003
x=1003

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