rezolva sistemul de ecuatie:
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Răspuns:
Din x+y=3 => x=3-y si inlocuim:
xy=-10 <=> y(3-y)=-10 <=> - y^2+3y+10=0 |*(-1)
y^2-3y-10=0
Delta= 9-4*(-10)=9+40=49 >0 =>
=> y1=(3+7)/2=10/2=5
y2=(3-7)/2=(-4)/2=-2
Daca y=5 => x=3-5=-2
Daca y=-2 => x=3+2=5