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a fost răspuns

Descompuneti in factori:
a) 4x²-9-(2x+3)
b) 9(x-2)²-4(3x-7)²
c) 4(5x+3)²-25(x-2)²
d) (2x² - 2x +5)² - (x² + 2x +2)²
e) [tex] 4x^{4} [/tex] - (x²-2x+3)²

Răspuns :

a).  ...=[2x+3(2x+3)][2x-3(2x+3)]=...=(8x+9)(-4x-9)= - (4x+9)(8x+9) ;
b).  ...=[3(x-2)+2(3x-7)][3(x-2)-2(3x-7)]=...=(9x-20)(-3x+8) ;
c).  ...=[2(5x+3)+5(x-2)][2(5x+3)-5(x-2)]=...=(15x-4)(5x+16) ;
d).  ...=(2x²-2x+5 + x²+2x+2)(2x²-2x+5-x²-2x-2) =...=(3x²+7)(x²-4x+3)=x(x-1)(3x²+7) ;
e).  ...   se procedeaza asemanator ! 

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