Vs.NaOH = 300 mL , p = 1,325 g/cm3(mL) , c% = 37%
p = ms/Vs => ms = pxVs = 300x1,325 = 397,5 g sol. NaOH
m.apa = 250 g
din sol. NaOH determinam md.NaOH
c% = mdx100/ms => md = msxc%/100 = 397,5x37/100 = 147 g NaOH
=> ms.finala = ms.NaOH + m.apa = 397,5 + 250 = 647,5 g
c%finala = mdx100/ms.finala = 147x100/647,5 = 22,7%