cantitati echimoleculare => nr egal de moli adica x:x
1mol 2*23g
CH₂-OH + 2Na -> CH₂-ONa + H₂
CH₂-OH 46x CH₂-ONa
xmoli
1mol...............23g
CH₃-CH₂-OH + Na -> CH₃-CH₂-ONa + [tex] \frac{1}{2} [/tex]H₂
xmoli..............23x
23x+46x=69x=69 => x=1mol
m etanol=n*M etanol=1*46g=46g
m glicol=n*M glicol=1*62g=62g
m amestec=46+62=108g
