Răspuns :
rezulta (√(x+1))²=(√(x²-x-2))²
x+1=x²-x-2
-x²+x+x+1+2=0
-x²+2x+3=0 inmultim -1
x²-2x-3=0
Δ=4+12=16
x1=(2-4)/2=-2/2=-1
x2=(2+4)/2=6/2=3
S={-1,3}
x+1=x²-x-2
-x²+x+x+1+2=0
-x²+2x+3=0 inmultim -1
x²-2x-3=0
Δ=4+12=16
x1=(2-4)/2=-2/2=-1
x2=(2+4)/2=6/2=3
S={-1,3}