Răspuns :
a+b+c=18 a,b,c-nr.pare consecutive ?=a,b,c a/..../ b/..../2/ c/...../4/ 18-2-4=12(suma egală) 12:3=4(a) 4+2=6(b) 4+4=8(c)
a+b+c=18 a,b,c-nr.pare consecutive ?=a,b,c a/..../ b/..../2/ c/...../4/ 18-2-4=12(suma egală) 12:3=4(a) 4+2=6(b) 4+4=8(c)