formula distantei este radical din toti termenii
a. EF = √( 12 -15 )²+ ( 5 -9)² = √9 +16 =√25 =5
b. EF= √(2-10)²+(7-13 )² = √64+36 = √100=10
c. EF =√(7+5)²+(- 3 -2 )²=√144+ 25 =√169 =13
d. EF = √( 21+3)²+(9-2)² = √576+49=√625 =25
2 . AB = √(√5)² +2² =√9=3
perim.patrat = 4·3 =12 si aria = 3² =9
AC=√(4-9)² +( 1 -6)²=√25+25 = √50 = 5√2
perim. = 4·5√2 = 20√2 si aria = (5√2)² =50