fie x lungimea drumului
in prima etapa [tex] \frac{2x}{7} [/tex] a ramas [tex] \frac{5x}{7} [/tex]
a doua etapa [tex] \frac{1}{4}. \frac{5x}{7}= \frac{5x}{28} [/tex]
a ramas [tex] \frac{5x}{7} - \frac{5x}{28}= \frac{15x}{28} [/tex]
a treia etapa [tex] \frac{1}{3}. \frac{15x}{28}= \frac{5x}{28} [/tex]
a ramas [tex] \frac{15x}{28}- \frac{5x}{28}= \frac{10x}{28}= \frac{5x}{14} =200 [/tex]
[tex]x= \frac{14.200}{5}=560 [/tex]
