a)
100% ....................... 1,421 kg Al impur
95% ........................... m.p = 1,35 kg Al Pur
1,35 kg m g
2Al + Fe2O3 --> Al2O3 + 2Fe
2x27 2x56
=> m = 1,35x2x56/2x27 = 2,8 kg Fe
b)
cele 2,8 kg Fe s-au obtinut la teoretic la 100%..... dar 90% cat..?
100% ............................ 2,8 kg Fe
90% ............................... Cp = 2,52 kg Fe
c)
2,52 kg md kg
Fe + 2HCl --> FeCl2 + H2
56 2x36,5
=> md = 2,52x2x36,5/56 = 3,285 kg HCl
c% = mdx100/ms => ms = mdx100/c%
= 3,285x100/7,3 = 45 kg sol. HCl