exercitiul 6
va rog mult
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Răspuns:
(n²-12n+36)/n²-6²=
(n²-2n·6+6²)/(n²-36)=
(n-6)²/n²-36=
[(n-6)²]/[(n-6)(n+6)]=(n-6)/(n+6)
n=-2
(-2-6)/(-2+6)=(-8/4)⁽²=-2