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Valeriacotorobai
a fost răspuns

[tex]A) \frac{4X-51}{3} - \frac{17-3X}{4} = \frac{x+5}{2}



[/tex][tex]A) \frac{4X-51}{3} - \frac{17-3X}{4} = \frac{x+5}{2} B) \frac{2x+1}{3} - \frac{X-2}{5} = \frac{7x+5}{15}



LA PUNCTUL A RASPUNSUL TEBUIE SA FIE 15
LA PUNCTUL B MULTIME VIDA[tex]A) \frac{4X-51}{3} - \frac{17-3X}{4} = \frac{x+5}{2} B) \frac{2x+1}{3} - \frac{X-2}{5} = \frac{7x+5}{15}



[/tex]

Răspuns :

Eminonis
Aducem la numitorul comun 12:
[tex] \frac{4(4x-51)-3(17-3x)}{12} = \frac{6(5+x)}{12} [/tex]
Eliminam numitorii.
16x-204-51+9x=30+6x
25x-255=30+6x
19x=285
x=15

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