[tex]\it e)\ 2\sqrt{15}-3\sqrt{10}x=8\sqrt{15}|_{:\sqrt5}\ \Rightarrow 2\sqrt3-3\sqrt2x=8\sqrt3|_{\cdot\sqrt2}\ \Rightarrow \\ \\ \\ \ \Rightarrow 2\sqrt6-6x=8\sqrt6\ \Rightarrow -6x=8\sqrt6-2\sqrt6\ \Rightarrow -6x=6\sqrt6|_{:(-6)}\ \Rightarrow x=-\sqrt6[/tex]
