Răspuns:
miu,C6H6=78g/mol
miu,C6H6Cl6=291g/mol
p=m,px100/m,i----> m,p=1560x90/100g= 1404g benzen pur
78g..............................291g
C6H6+ 3CL2---> C6H6Cl6
1404g............................x
x=m,teoretica=5238g C6H6Cl6
m,practic= 5238x80/100g=4190,4g C6H6Cl6
Explicație: