Răspuns:
Explicație pas cu pas:
a) 2⁻³⁰ si 3⁻²⁰
2⁻³⁰ = 2⁻³ˣ¹⁰ = (2⁻³)¹⁰ = (1/8)¹⁰
3⁻²⁰ = 3⁻²ˣ¹⁰ = (3⁻²)¹⁰ = (1/9)¹⁰ =>
(1/8)¹⁰ > (1/9)¹⁰ => 2⁻³⁰ > 3⁻²⁰
b) 5⁻¹⁴ si 3⁻²¹
5⁻¹⁴ = 5⁻²ˣ⁷ = (5⁻²)⁷ = (1/25)⁷
3⁻²¹ = 3⁻³ˣ⁷ = (3⁻³)⁷ = (1/27)⁷
(1/25)⁷ > (1/27)⁷ => 5⁻¹⁴ > 3⁻²¹
c) 2⁻⁷⁵ si 3⁻⁴⁵
2⁻⁷⁵ = 2⁻⁵ˣ¹⁵ = (2⁻⁵)¹⁵ = (1/32)¹⁵
3⁻⁴⁵ = 3⁻³ˣ¹⁵ = (3⁻³)¹⁵ = (1/27)¹⁵
(1/32)¹⁵ < (1/27)¹⁵ => 2⁻⁷⁵ < 3⁻⁴⁵
